Index exceeds the number of array elements (1) (2024)

4 views (last 30 days)

Show older comments

Jonas Freiheit on 9 Sep 2020

  • Link

    Direct link to this question

    https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1

  • Link

    Direct link to this question

    https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1

Commented: Jonas Freiheit on 10 Sep 2020

Accepted Answer: Kojiro Saito

Open in MATLAB Online

%When I try to perform a row interchange for 'b' vector It tells me it exceeds the no of array elements. This is an attempt to perform partial pivoting for matrix A and vector b separately.

Thanks

A = [1 2 3;4 2 -1; 3 2 3];

b = [1; 3; 2];

k = 1;

A = pivoting(A,k)

function [A, b, flag] = pivoting(A, b, k)

n = size(A,1);

flag = 0;

for k=1:n-1

[big, i]=max(abs(A(k:n,k)))

ipr=i+k-1

if ipr~=k

A([k,ipr],:)=A([ipr,k],:)

b([k,ipr])=b([ipr,k])

end

end

end

0 Comments

Show -2 older commentsHide -2 older comments

Sign in to comment.

Sign in to answer this question.

Accepted Answer

Kojiro Saito on 9 Sep 2020

  • Link

    Direct link to this answer

    https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#answer_491890

  • Link

    Direct link to this answer

    https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#answer_491890

Open in MATLAB Online

It's because you're trying to manipulate b in line,

b([k,ipr])=b([ipr,k])

but, you're inputting as follows.

k = 1;

A = pivoting(A,k)

so, in function pivoting, b (second input variable) is scalar (1).

You just need to input three variables.

% A = pivoting(A,k)

A = pivoting(A,b,k)

9 Comments

Show 7 older commentsHide 7 older comments

Jonas Freiheit on 9 Sep 2020

Direct link to this comment

https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1002565

  • Link

    Direct link to this comment

    https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1002565

Edited: Jonas Freiheit on 9 Sep 2020

That worked for me but, Is there another way to solve this program successfully without changing the pivoting function and only the code in the for loop?

Thanks for the help Kojiro!

Kojiro Saito on 9 Sep 2020

Direct link to this comment

https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1003276

  • Link

    Direct link to this comment

    https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1003276

Edited: Kojiro Saito on 9 Sep 2020

Open in MATLAB Online

It didn't mean changing pivoting function. You're calling pivoting with two inputs (A and k),

A = [1 2 3;4 2 -1; 3 2 3];

b = [1; 3; 2];

k = 1;

A = pivoting(A,k)

but I suggested that you would call pivoting with three inputs (A, b and k)

A = [1 2 3;4 2 -1; 3 2 3];

b = [1; 3; 2];

k = 1;

A = pivoting(A,b,k)

Jonas Freiheit on 10 Sep 2020

Direct link to this comment

https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1003558

  • Link

    Direct link to this comment

    https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1003558

Sorry what I meant was is it possible to do it with only calling pivoting with two inputs (A and k)?

Kojiro Saito on 10 Sep 2020

Direct link to this comment

https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1003591

  • Link

    Direct link to this comment

    https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1003591

Open in MATLAB Online

I see. Actually, k is initialized in pivoting function, so you don't need to input it.

The following would work.

A = [1 2 3;4 2 -1; 3 2 3];

b = [1; 3; 2];

%k = 1;

A = pivoting(A)

function [A, flag] = pivoting(A)

n = size(A,1);

flag = 0;

for k=1:n-1

[big, i]=max(abs(A(k:n,k)))

ipr=i+k-1

if ipr~=k

A([k,ipr],:)=A([ipr,k],:)

%b([k,ipr])=b([ipr,k])

end

end

end

Jonas Freiheit on 10 Sep 2020

Direct link to this comment

https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1003606

  • Link

    Direct link to this comment

    https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1003606

Edited: Jonas Freiheit on 10 Sep 2020

Sorry sorry, I mean only by changing this code:

for k=1:n-1

[big, i]=max(abs(A(k:n,k)))

ipr=i+k-1

if ipr~=k

A([k,ipr],:)=A([ipr,k],:)

b([k,ipr])=b([ipr,k])

end

end

end

Thanks, don't mean to annoy you, I'm trying to learn how to change the source code without changing the pivoting function.

Kojiro Saito on 10 Sep 2020

Direct link to this comment

https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1003627

  • Link

    Direct link to this comment

    https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1003627

Open in MATLAB Online

The following is what you want to do?

A = [1 2 3;4 2 -1; 3 2 3];

b = [1; 3; 2];

%k = 1;

n = size(A,1);

for k=1:n-1

[big, i]=max(abs(A(k:n,k )))

ipr=i+k-1

if ipr~=k

A([k,ipr],:)=A([ipr,k ],:)

b([k,ipr])=b([ipr,k ])

end

end

Jonas Freiheit on 10 Sep 2020

Direct link to this comment

https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1003639

  • Link

    Direct link to this comment

    https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1003639

Yeah, including this code with only changing from the bold text code.

A = [1 2 3;4 2 -1; 3 2 3];

b = [1; 3; 2];

k = 1;

A = pivoting(A,k)

function [A, b, flag] = pivoting(A, b, k)

n = size(A,1);

flag = 0;

for k=1:n-1 %Here

[big, i]=max(abs(A(k:n,k)))

ipr=i+k-1

if ipr~=k

A([k,ipr],:)=A([ipr,k],:)

b([k,ipr])=b([ipr,k])

end

end

end %End

Thanks, Kojiro

Kojiro Saito on 10 Sep 2020

Direct link to this comment

https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1003666

  • Link

    Direct link to this comment

    https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1003666

It's not possible only changing the bold text code because the funtion pivoting requires three inputs, so you need to modify input variables so that it allows two inputs.

Jonas Freiheit on 10 Sep 2020

Direct link to this comment

https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1003687

  • Link

    Direct link to this comment

    https://uk.mathworks.com/matlabcentral/answers/590884-index-exceeds-the-number-of-array-elements-1#comment_1003687

Alright that makes sense,

Thanks for the help Kojiro!

Sign in to comment.

More Answers (0)

Sign in to answer this question.

See Also

Categories

MATLABLanguage FundamentalsMatrices and ArraysMatrix Indexing

Find more on Matrix Indexing in Help Center and File Exchange

Tags

  • partial pivoting
  • index
  • elements
  • array
  • matlab
  • error
  • row interchange
  • vector
  • matrix

Products

  • MATLAB

Release

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

An Error Occurred

Unable to complete the action because of changes made to the page. Reload the page to see its updated state.


Index exceeds the number of array elements (1) (12)

Select a Web Site

Choose a web site to get translated content where available and see local events and offers. Based on your location, we recommend that you select: .

You can also select a web site from the following list

Americas

  • América Latina (Español)
  • Canada (English)
  • United States (English)

Europe

  • Belgium (English)
  • Denmark (English)
  • Deutschland (Deutsch)
  • España (Español)
  • Finland (English)
  • France (Français)
  • Ireland (English)
  • Italia (Italiano)
  • Luxembourg (English)
  • Netherlands (English)
  • Norway (English)
  • Österreich (Deutsch)
  • Portugal (English)
  • Sweden (English)
  • Switzerland
    • Deutsch
    • English
    • Français
  • United Kingdom(English)

Asia Pacific

  • Australia (English)
  • India (English)
  • New Zealand (English)
  • 中国
  • 日本Japanese (日本語)
  • 한국Korean (한국어)

Contact your local office

Index exceeds the number of array elements (1) (2024)

FAQs

How to solve index exceeds the number of array elements index must not exceed 1? ›

- The error message indicates that you're trying to access an element with an index larger than the array size, which leads to an "out of bounds" error. - To fix this issue, make sure you're using valid indices within the array's size, or consider increasing the array size if necessary to accommodate the desired index.

How do you find the index number of an element in an array? ›

JavaScript Array findIndex()

The findIndex() method executes a function for each array element. The findIndex() method returns the index (position) of the first element that passes a test. The findIndex() method returns -1 if no match is found.

What does "index exceeds array bounds" mean? ›

It means that the index number is more than the array elements.

How do you find the index of a maximum number in an array? ›

Find the index of the largest number in an array
  1. Assign array value. Assume largest number as array's first value and its index as 0.
  2. Iterate array using a for loop.
  3. Check max value is smaller than array current value, if true reassign the max value and its index position. Output.
Jun 10, 2021

How do you change the index number of an array? ›

Using the splice() Method

The splice() method is used to change an array by adding, removing, or replacing elements. This method modifies the original array. The first argument of the splice() method is the start index, which is the index at which to start changing the array.

How do you get the element at the index of an array? ›

The indexOf() method of Array instances returns the first index at which a given element can be found in the array, or -1 if it is not present.

What is index number in array? ›

Element index: It is the sequential number (index/key) assigned to the element where the first element of the array is assigned 0. It can also be defined as the number of elements prior to that particular element in the array. Size of a single element: Elements in the array need to be of the same data type or object.

How do you find the index of an ArrayList? ›

The indexOf() method of ArrayList returns the index of the first occurrence of the specified element in this list, or -1 if this list does not contain the element. Syntax : public int IndexOf(Object o) obj : The element to search for.

How to find index number? ›

The aggregative method is commonly used to calculate the price index. In this method, the index number (P) = the sum of all the values of all the commodities in the current year (P1) divided by the sum of all the values of the same commodities in the base year (P0) and multiplied by 100.

How do you fix array index out of bounds? ›

To correct it, either change the declaration of the array, or change the formula so the index values stay within the boundaries of the array. Run-time errors are reported only when the DEBUG symbol is defined.

How do I ignore an array index out of bound exception? ›

Use a for loop with the size of the array: Instead of using a traditional for loop with a fixed number of iterations, you can use a for loop that iterates over the array based on its size. This way, the loop will not try to access an element that does not exist.

How to prevent array index out of bounds exception in Java? ›

3. How to Avoid ArrayIndexOutOfBoundsException?
  1. 3.1. Remembering the Start Index. We must always remember that the array index starts at 0 in Java. ...
  2. 3.2. Correctly Using the Operators in Loops. Incorrectly initializing the loop variable to index 1 may result in ArrayIndexOutOfBoundsException. ...
  3. 3.3. Using Enhanced for Loop.
Jan 8, 2024

How do you find the index of a number in an array? ›

The findIndex() method of Array instances returns the index of the first element in an array that satisfies the provided testing function. If no elements satisfy the testing function, -1 is returned. See also the find() method, which returns the first element that satisfies the testing function (rather than its index).

How do you find the maximum number of an array? ›

One approach to find the maximum and minimum element in an array is to first sort the array in ascending order. Once the array is sorted, the first element of the array will be the minimum element and the last element of the array will be the maximum element.

What is the highest index that can be used with an array? ›

The indices allowed fall within a range, typically from 0 to the length of the array minus 1 (for a zero index origin) or 1 to the length of the array (for a 1 index origin). Thus, the highest index is a function of the index origin.

How do you increase all elements in an array by 1? ›

  1. Declare an array of some fixed size(i.e 4) and define all its element at the time of declaration.
  2. Create a function an pass this array to this function as a parameter.
  3. Inside this for loop, run a for loop from 0 to size-1, accessing each element of the array, add 1 to it and store the result in the same array index.

How do you find the maximum element index in an array in C++? ›

Find the maximum of Array using Library Function:

Most of the languages have a relevant max() type in-built function to find the maximum element, such as std::max_element in C++. We can use this function to directly find the maximum element.

References

Top Articles
Latest Posts
Article information

Author: Edmund Hettinger DC

Last Updated:

Views: 6541

Rating: 4.8 / 5 (58 voted)

Reviews: 81% of readers found this page helpful

Author information

Name: Edmund Hettinger DC

Birthday: 1994-08-17

Address: 2033 Gerhold Pine, Port Jocelyn, VA 12101-5654

Phone: +8524399971620

Job: Central Manufacturing Supervisor

Hobby: Jogging, Metalworking, Tai chi, Shopping, Puzzles, Rock climbing, Crocheting

Introduction: My name is Edmund Hettinger DC, I am a adventurous, colorful, gifted, determined, precious, open, colorful person who loves writing and wants to share my knowledge and understanding with you.